Answer : The mass of 1.50 mole of iron (III) sulfate is, Explanation : Given, Moles of iron (III) sulfate = 1.50 mole Molar mass of iron (III) sulfate = 399.88 g/mole The formula of iron (III) sulfate is, Formula used : Now put all the given values in this formula, we get: Therefore, the mass of 1.50 mole of iron (III) sulfate is, Advertisement
›› Iron molecular weight. Molar massofFe = 55.845 g/mol. ... Finding molarmassstarts with units ofgrams per mole (g/mol). When calculating molecular weight ofa chemical compound, it tells us how many grams are in one mole ofthat substance. The formula weight is simply the weight in atomic massunits ofall the atoms in a given formula.
One would go to trim all off around yourself, so I don't herself. It has a formal off every two s o for three, and it's Moller Mas is three ninety nine point eighty eight gram per mall. That means it's one more. Contains three ninety nine point eight. Did Crumb. Therefore, one point two three mall will contain simply this mass times they small.
Iron (III) sulfate Iron (III) sulfate (or ferric sulfate ), is a family of inorganic compounds with the formula Fe 2 (SO 4) 3 (H 2 O) n. A variety of hydrates are known, including the most commonly encountered form of "ferric sulfate". Solutions are used in dyeing as a mordant, and as a coagulant for industrial wastes.
What is the molar mass of iron 3 sulfate? 399.88 g/mol Iron(III) sulfate/Molar mass What is the molecular formula of iron III sulphate? Fe2(SO4)3 Iron(III) sulfate/Formula What Colour is Fe3+? Identifying transition metal ions What Colour is iron nitrate solution? Color: Very faint yellow to colorless.
Molar mass: 159.69 g/mol Formula: Fe2O3 Density: 5.24 g/cm³ Melting point: 1,565 °C 1 Sponsored by The Penny Hoarder What companies will send people money when they're asked nicely? Here are five companies that will help. Read More 105 Tolulope Oyinlola Former Production Manager (2016–2021) Author has 198 answers and 72.7K answer views Jan 23
What is the mass, in grams, of 1.223 mol of iron (III) sulfate? Solutions Verified Solution A Solution B Create an account to view solutions By signing up, you accept Quizlet's Terms of Service and Privacy Policy Continue with Google Continue with Facebook Sign up with email Recommended textbook solutions Pearson Chemistry
Expert Answer Transcribed image text: Part A What is the mass of 1.282 mol of iron (III) sulfate? Express your answer in grams to four significant figures. IVO AQ ? m= g Submit Request Answer Part B How many moles of ammonium ions are in 6.935 g of ammonium carbonate? Express your answer in moles to four significant figures.
As a reminder, a mole of a chemical element is the amount of substance containing 6,02214076 ⋅ 1023 6, 02214076 ⋅ 10 23 of elementary entities of that element (atoms, molecules, elemental particle, etc.). This number corresponds to the number of Avogadro N A N A . N A = 6,02214076 ⋅ 1023mol−1 N A = 6, 02214076 ⋅ 10 23 m o l - 1
The molar mass is 2 x 55.845 + 3 x 16 = 159.69 g/mol So, the iron is 111.69 / 159.69 = 0.6994 times the mass of Fe2O3. 10kg of iron would require 10/0.6994 = 14.298kg of Fe2O3 More answers below Caleb Rose in Chemistry & Software Engineering, Central New Mexico Community College (Graduated 2018) 4 y Equation: 3O2+ 4Fe => 2Fe2O3 Conversions used: